Johns Hopkins University
EN.625 728
Theory of Probability (625.728)
Spring 2026
Page: 1 of 4
Due: 3/9/26
Theory of Probability (625.728) { Spring 2026
All random variables are assumed to be defined on (Ω; A; µ). We prove Chapter 3,
Theorem 5(i):
Theorem 5 (i): Assume that the sequence of random variables fXng converges mutually
in measure. Then ther
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Theory of Probability (625.728)
Spring 2026
Page: 1 of 4
Due: 3/9/26
Theory of Probability (625.728) { Spring 2026
All random variables are assumed to be defined on (Ω; A; µ). We prove Chapter 3,
Theorem 5(i):
Theorem 5 (i): Assume that the sequence of random variables fXng converges mutually
in measure. Then there is a subsequence fXnkg of fXng and a random variable X0 such that
fXnkg converges to X0 a.e. and in measure.
Proof): Choose an integer n1 ≥ 1 such that
µ jXm - Xn1j ≥ 12 ≤ 1 2 for m ≥ n1 :
Choose n2 > n1 such that
µ jXm - Xn2j ≥ 212 ≤ 212 for m ≥ n2 :
Using induction, we can choose a sequence 1 ≤ n1 < n2 < n3 < · · · such that
µ jXm - Xnkj ≥ 21k ≤ 21k for m ≥ nk :
In particular, nk+1 > nk, so that
µ jXnk+1 - Xnkj ≥ 21k ≤ 21k for k ≥ 1:
Consider the sets
Ak = ! : jXnk+1 - Xnkj ≥ 21k k ≥ 1 ;
and define
A =
1 \ k
=1
1 [ ν=k
A
ν :
The set A has measure zero. Indeed, using countable subadditivity, we have for each k ≥ 1,
Theory of Probability (625.728)
Spring 2026
Page: 2 of 4
Due: 3/9/26
0 ≤ µ(A) ≤ µ
1 [ ν=k
A
ν! ≤ 1
2k-1 ; (1)
which implies that µ(A) = 0. This follows from the continuity property of measures.
Observe that for each ! = 2 A the following infinite series converges
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