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Basic Engineering Circuit Analysis (11th Edition) See all exercises

Chapter 7, End of Chapter, PROBLEMS, Exercise 7.112

Here is the step-by-step explanation, verified by an educator:

Step 1 of 3

At , the switch is opened and the circuit is under steady state. The inductor acts as a short circuit.

Calculate the values of and .

Step 2 of 3

Now,

Calculate the value of and .

Step 3 of 3

The equation for current will be realized as:

By analysing the initial conditions of the circuit the values of and are obtained as:

Hence, realize the value of current .

Search 7 e

5/30/26, 7:55 PM ✅ Solved: Chapter 7, Problem 7.112 - Basic Engineering Circuit Analysis (11th Edition)

https://www.coursehero.com/textbook-solutions/Basic-Engineering-Circuit-Analysis-11th-Edition-9781118539293-1198/Chapter-7-Problem-7112-2060427/ 1/4

P,

Ex 7.111 P, Ex 7.113

All Textbook Solutions / Basic Engineering Circuit Analysis (11th Edition) / Ch 7, End of Chapter, Ex 7.112

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Final answer

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i (t) = (B1 + B2t) e-5t

= (3 + (0) t) e-5t

= 3e-5t

i (t) = 3e-5t

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5/30/26, 7:55 PM ✅ Solved: Chapter 7, Problem 7.112 - Basic Engineering Circuit Analysis (11th Edition)

https://www.coursehero.com/textbook-solutions/Basic-Engineering-Circuit-Analysis-11th-Edition-9781118539293-1198/Chapter-7-Problem-7112-2060427/ 2/4

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